Diketahui vektor A = ( 3 -2 1 ) B = ( -3 4 5 ) C = ( 5 -3 2 ) tentukan
a. a+b+2c
b.2a+2c
c.5a-3c
a.
A + B + 2C
= (3, -2, 1) + (-3, 4, 5) + 2(5, -3, 2)
= (3, -2, 1) + (-3, 4, 5) + (10, -6, 4)
= (10, -4, 10)
b.
2A + 2C
= 2(3, -2, 1) + 2(5, -3, 2)
= (6, -4, 2) + (10, -6, 4)
= (16, -10, 6)
c.
5A - 3C
= 5(3, -2, 1) - 3(5, -3, 2)
= (15, -10, 5) - (15, -9, 6)
= (0, -1, -1) [answer.2.content]
a. a+b+2c
b.2a+2c
c.5a-3c
A + B + 2C
= (3, -2, 1) + (-3, 4, 5) + 2(5, -3, 2)
= (3, -2, 1) + (-3, 4, 5) + (10, -6, 4)
= (10, -4, 10)
b.
2A + 2C
= 2(3, -2, 1) + 2(5, -3, 2)
= (6, -4, 2) + (10, -6, 4)
= (16, -10, 6)
c.
5A - 3C
= 5(3, -2, 1) - 3(5, -3, 2)
= (15, -10, 5) - (15, -9, 6)
= (0, -1, -1) [answer.2.content]